Question

${\left[{\left\{{(-\frac{1}{2})}^2\right\}}^{-2}\right]}^{-1}=?$

$\left(a\right)\frac{1}{16}$

(b)16

$\left(c\right)-\frac{1}{16}$

(d-16)

Answer 1

${\left[{\left\{{(-\frac{1}{2})}^2\right\}}^{-2}\right]}^{-1}={\left(\frac{-1}{2}\right)}^{2\times (-2)(-1)}={\left(\frac{-1}{2}\right)}^4$

$=\left(\frac{-1}{2}\right)\left(\frac{-1}{2}\right)\left(\frac{-1}{2}\right)\left(\frac{-1}{2}\right)=\frac{1}{16}$