Question

$\left[\mathrm{Ti}{\left(H_{2}O\right)}_6\right]C{l}_3$ has $Ti$ atom____ hybridiate with unpaired _____ electrons.

• A. $d^{2}s{p}^3,1$
• B. $d^{2}s{p}^3,4$
• C. $s{p}^3{d}^2,1$
• D. $s{p}^3{d}^2,3$

Answer 1

The correct option is D $s{p}^3{d}^2,3$

As, the ligand $H_{2}O$ is a weak field ligand and the coordination number is $6$. So, the hybridization is $s{p}^3{d}^2$

$\left[Ti\right(H_{2}O{)}_6{]}^{3+}C{l}_3$

$T{i}^{3+}\Rightarrow \left[Ar\right]3d^1$

It has only one unpaired electron with magnetic monet of $1.732$ $B.M$.