-a-2 b-c- a-b- a-b-c-A- 2-a- b- c-B- 0C- 3-a- b- c-D- -a- b- c-

The correct option is B 0[a+2b c,a b,a b c] =(a+2b c).{(a b)× (a b c)} =(a+2b c).{ (a×b) (a×c) (b×a)+(b×c)} =[a,b,c] 2[b,a,c]=3[a,b,c] ...

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Multiplication of a Vector by a Scalar

[a⃗+2 b⃗-c⃗, ...

Question

$[\to a + 2 \to b - \to c, \to a - \to b, \to a - \to b - \to c] =$

2 [\to a, \to b, \to c]

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3 [\to a, \to b, \to c]

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[\to a, \to b, \to c]

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Similar questions

\to a =^i +^j +^k

\to b = - 3^i +^k

\to c =^i + 2^j + 3^k

A)

[\to a \times \to b

\to b \times \to c

\to c \times \to a]

B)

[\to a + \to b

\to b + \to c

\to c + \to a]

C)

[\to a

\to b

\to c]

[\to a

\to b

\to c]^{- 1}

D)

[\to a - \to b

\to b - \to c

\to c - \to a]

(\to a + \to b) \times (\to a - \to b) + (\to b + \to c) \times (\to b - \to c) + (\to c + \to a) \times (\to c - \to a) =

\to A = \to b \times \to c, \to B = \to c \times \to a, \to C = \to a \times \to b

\to A \times (\to B \times \to C)

\to B \times (\to C \times \to A)

\to C \times (\to A \times \to B)

| \to a | = 1, ∣ ∣ \to b ∣ ∣ = \sqrt{2}

| \to c | = \sqrt{3}

\to a ⊥ (\to b + \to c)

\to b ⊥ (\to c + \to a)

\to c ⊥ (\to a + \to b)

∣ ∣ \to a + \to b + \to c ∣ ∣

| \to a | = 3, ∣ ∣ \to b ∣ ∣ = 4, | \to c | = 5, \to a ⊥ (\to b + \to c), \to b ⊥ (\to c + \to a)

\to c ⊥ (\to a + \to b)

\sqrt{2} ∣ ∣ \to a + \to b + \to c ∣ ∣

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