d - a - a - b - c - d simplifies to-

The correct option is A ( b d ) [ a c d ] a⃗×( b⃗×( c⃗×d⃗ #160; ) #160; ) a⃗×( ( b⃗ .d⃗ #160; ) c⃗ ( b⃗ .c⃗ #160; ) d⃗ #160; ...

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Byju's Answer

Standard XII

Mathematics

Definition of Relations

d × a . a × b...

Question

$(\to d \times \to a) . (\to a \times (\to b \times (\to c \times \to d)))$ simplifies to:

(\to b \to d) [\to a \to c \to d]

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(\to b \to c) [\to a \to b \to d]

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(\to b \to a) [\to a \to b \to d]

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(\to b \to c) [\to a \to c \to d]

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Solution

The correct option is A $(\to b \to d) [\to a \to c \to d]$
$\to a \times (\to b \times (\to c \times \to d))$
$\to a \times ((\to b . \to d) \to c - (\to b . \to c) \to d) = (\to a \times \to c) (\to b . \to d) - (\to a \times \to d) (\to b . \to c)$
$∴ \to d . (\to a \times (\to b \times (\to c \times \to d)))$
$= \to d (\to a \times \to c) (\to b . \to d) - \to d . (\to a \times \to c) (\to b \times \to c) = (\to b . \to d) [\to a \to c \to d]$

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Similar questions

Q. Prove that

[a, b + c, d] = [a b d] + [a c d]

In the given figure, if $∠ B A D = ∠ C A D, ∠ A B D = ∠ A C D,$ then which of the following is false?

In the given figure, if $∠ B A D = ∠ C A D, ∠ A B D = ∠ A C D,$ then which of the following is true ?

In the given figure, BD bisects $∠ A B C$ and BD is perpendicular to AC. Which of the following statements are correct?

In the given figure, if $∠ B A D = ∠ C A D, ∠ A B D = ∠ A C D,$ then which of the following is false?
a) $△ A B D ≅ △ A C D$ by SAS postulate
b) $△ A B D ≅ △ A C D$ by AAS postulate
c)AB = AC
d)BD = CD

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(→d×→a).(→a×(→b×(→c×→d))) simplifies to:

The correct option is A (→b→d)[→a→c→d]→a×(→b×(→c×→d))→a×((→b.→d)→c−(→b.→c)→d)=(→a×→c)(→b.→d)−(→a×→d)(→b.→c)∴→d.(→a×(→b×(→c×→d)))=→d(→a×→c)(→b.→d)−→d.(→a×→c)(→b×→c)=(→b.→d)[→a→c→d]

$(\to d \times \to a) . (\to a \times (\to b \times (\to c \times \to d)))$ simplifies to: