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Byju's Answer
Standard XII
Mathematics
Definition of Relations
[ ∼ p⇒ p ]∧ [...
Question
[
(
∼
p
)
⇒
p
]
∧
[
p
⇒
(
∼
p
)
]
is
A
a tautology.
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B
a contradiction.
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C
a tautology and a contradiction.
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D
neither a tautology nor a contradiction.
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Solution
The correct option is
B
a contradiction.
p
∼
p
∼
p
⇒
p
p
⇒
∼
p
(
∼
p
⇒
p
)
∧
(
p
⇒
∼
p
)
T
F
T
F
F
F
T
F
T
F
From the above table, the truth value of the expression
(
∼
p
⇒
p
)
∧
(
p
⇒
∼
p
)
is always F. Hence it's a contradiction.
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