a-b- - c-d- is equal to

The correct options are A a⃗.{b⃗× ( c⃗×d⃗ ) } B ( a⃗.c⃗ ) ( b⃗.d⃗ ) ( a⃗.d⃗ ) ( b⃗.c⃗ ) C { ( a⃗×b⃗ )×c⃗}.d⃗ D ( d⃗×c⃗ ). ( b⃗×a⃗ ) And ...

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Cartesian Product

a⃗×b⃗ . c⃗×d⃗...

Question

$(\to a \times \to b) . (\to c \times \to d)$ is equal to

\to a . {\to b \times (\to c \times \to d)}

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(\to a . \to c) (\to b . \to d) - (\to a . \to d) (\to b . \to c)

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{(\to a \times \to b) \times \to c} . \to d

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(\to d \times \to c) . (\to b \times \to a)

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Similar questions

(\to b \times \to c) . (\to a \times \to d) + (\to c \times \to a) . (\to b \times \to d)

+ (\to a \times \to b) . (\to c \times \to d) =

(\to a \times \to b) . (\to c \times \to d) + (\to b \times \to c) . (\to a \times \to d) + (\to c \times \to a) . (\to b \times \to d)

\to a = \to b + \to c, \to b \times \to d = 0

\to c . \to d = 0

\frac{\to d \times (\to a \times \to d)}{^{2}}

\to a, \to b, \to c, \to d

(\to a \times \to b) \times (\to c \times \to d) + (\to a \times \to c) \times (\to d \times \to b) + (\to a \times \to d) \times (\to b \times \to c)

\to a \times \to b = \to c \times \to d

\to a \times \to c = \to b \times \to d

\to a - \to d, \to b - \to c

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