a-i- i- a-j- j- a-k- k- is equal to

The correct option is D a⃗ Let #160; a⃗ #160;be #160; pi⃗ + qj⃗ + rk⃗ ∴ ( a⃗.i⃗ )i⃗+ ( a⃗.j⃗ )j⃗+ ( a⃗.k⃗ )k⃗ = pi⃗+ qj⃗+ rk⃗ Thi ...

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a⃗.i⃗ i⃗+ a⃗....

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$(\to a . \to i) \to i + (\to a . \to j) \to j + (\to a . \to k) \to k$ is equal to

\to i + \to j + \to k

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\to a

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3 \to a

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None of these

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\to i \times (\to a \times \to i) + \to j \times (\to a \times \to j) + \to k \times (\to a \times \to k)

\to i \times (\to a \times \to i) + \to j \times (\to a \times \to j) + \to k \times (\to a \times \to k)

\to i, \to j, \to k

\to a = \to i + \to j + \to k, \to a = 2 \to i + \to k, \to c = 2 \to i + \to j + \to k; \to d = \to i + \to j + 2 \to k

(\to a \times \to b) \times (\to c \times \to d) = [\to a \to b \to d] \to c - [\to a \to b \to c] \to d

[\to i + \to j, \to j + \to k, \to k + \to i]

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\to j

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