- b- c- d- a- a- c- d- b- a- d- b- c- a- b- c- a-

The correct option is A #10;0 #10; [b⃗c⃗d⃗ ]a⃗ [a⃗c⃗d⃗ ]b⃗ +[a⃗d⃗b⃗ ]c⃗ [a⃗b⃗c⃗ ]a⃗ [b⃗· (c⃗×d⃗ )]a⃗ [a⃗· (c⃗×d⃗ )]b⃗ +[d⃗· (d⃗×b⃗ )]c⃗ [a⃗· ...

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Unit Vectors

[ b⃗ c⃗ d⃗] a...

Question

$[\to b \to c \to d] \to a - [\to a \to c \to d] \to b + [\to a \to d \to b] \to c - [\to a \to b \to c] \to a =$

\to a

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\to b

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¯ ¯ c

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\to a + \to b + \to c = 0, | \to a | = 3, ∣ ∣ \to b ∣ ∣ = 5, | \to c | = 7

\to a

\to b

\to a + \to b + \to c = 0, | \to a | = 3, ∣ ∣ \to b ∣ ∣ = 5

| \to c | = 7

\to a

\to b

\to a + 2 \to b + 3 \to c = 0

\to a \times \to b + \to b \times \to c + \to c \times \to a

λ (\to b \times \to c)

λ

\to a, \to b, \to c

| \to a + \to b + \to c | = 1, \to c = λ (\to a \times \to b)

| \to a | = \frac{1}{\sqrt{2}}, | \to b | = \frac{1}{\sqrt{3}}, | \to c | = \frac{1}{\sqrt{6}}

\to a

\to b

\to a

\to b

\to r = γ (\to b + \to a), \to r = μ (\to b - \to a)

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