The correct option is D None of the above {y y^2=36} ⇒ y^2=36 ⇒ y=±√(36)=± 6 ∴ y={ 6,6} is finite set with cardinality 2 ...

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y: y2=36 is a...

Question

${y : y^{2} = 36}$ is a ________ set.

singletan

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empty

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infinite

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None of the above

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Solution

The correct option is D None of the above
${y y^{2} = 36}$
$\Rightarrow y^{2} = 36$
$\Rightarrow y = \pm \sqrt{36} = \pm 6$
$∴ y = {- 6, 6}$ is finite set with cardinality $2$

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