Length, breadth and height of a cuboidal tank are in the ratio of 6:2:1.The lateral surface area of the tank is 400 sq.m.

Find i) Volume of the tank.

ii)If water flows into the tank at a rate of 10 cubic meters per minute, calculate no. of hours for the tank to get completely filled.

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Solution

Given 2h(l+b) = 400

Let height h be ‘x’ then l = 6x; b = 2x

$\Rightarrow$ 2x(6x +2x) = 400

$\Rightarrow$ $16 x^{2} = 400$

$\Rightarrow$ x = 5

So, h = 5m, l = 30m and b =10 m

i.) Volume of the tank = lbh = 1500 $m^{3}$

ii.) Total time required= $\frac{1500}{10}$ =150 minutes = 2.5 hours.

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Length, breadth and height of a cuboidal tank are in the ratio of 6:2:1.The lateral surface area of the tank is 400 sq.m. Find i) Volume of the tank. ii)If water flows into the tank at a rate of 10 cubic meters per minute, calculate no. of hours for the tank to get completely filled.

Given 2h(l+b) = 400 Let height h be ‘x’ then l = 6x; b = 2x ⇒2x(6x +2x) = 400 ⇒16x2=400 ⇒ x = 5 So, h = 5m, l = 30m and b =10 m i.) Volume of the tank = lbh = 1500m3 ii.) Total time required= 150010 =150 minutes = 2.5 hours.

Length, breadth and height of a cuboidal tank are in the ratio of 6:2:1.The lateral surface area of the tank is 400 sq.m.

Find i) Volume of the tank.

ii)If water flows into the tank at a rate of 10 cubic meters per minute, calculate no. of hours for the tank to get completely filled.

Given 2h(l+b) = 400

Let height h be ‘x’ then l = 6x; b = 2x

$\Rightarrow$ 2x(6x +2x) = 400

$\Rightarrow$ $16 x^{2} = 400$

$\Rightarrow$ x = 5

So, h = 5m, l = 30m and b =10 m

i.) Volume of the tank = lbh = 1500 $m^{3}$

ii.) Total time required= $\frac{1500}{10}$ =150 minutes = 2.5 hours.