Let breadth , b = x m
length , l = (x+6)m
given perimeter of rectangle = 64m
Formula for perimeter of rectangle = 2 (l+b)
we know perimeter
and substitut b and l
64=2 (x+6 +x) m
64=2 (2x+6)
2x+6=64÷2
2x=32-6
x=26÷2=13m
We know we took breadth b = xm
so breadth , b = 13m
and length of the rectangle exceeds its breadth by 6 meter
l = x+6 = 19m