CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Length of a rectangle is 4 cm more than its breadth, perimeter of the rectangle is 40 cm. Frame simultaneous linear equations in two variables representing the following information:

A
xy=4,x+y=20
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
xy=4,x+y=40
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x+y=4,x+y=20
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x+y=4,x+y=40
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A xy=4,x+y=20
Let the length of rectangle be x
Let the breadth of rectangle be y
As per given question length of rectangle is 4 cm more than its breadth, so the following equation can be formed
xy=4 ..........(1)
We know, perimeter of a rectangle is 2( length + breadth)
Therefore, 2(x+y)=40
2x+2y=40
x+y=20 ......(2)
Therefore the given equations are x+y=20 and xy=4.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Framing Algebraic Equations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon