Length of a rectangle is $5$ units more than its breadth. Express its perimeter in polynomial form.

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Solution

Given,
Length of a rectangle is $5$ units more than its breadth.Perimeter is defined as total length of contour.
Let breadth of rectangle be $a$ units then its length will be $a + 5$ units. Then perimeter of rectangle is given by $2 * (a + a + 5) = 4 a + 10$ units

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Length of a rectangle is 5 units more than its breadth. Express its perimeter in polynomial form.

Given,Length of a rectangle is 5 units more than its breadth.Perimeter is defined as total length of contour.Let breadth of rectangle be a units then its length will be a+5 units. Then perimeter of rectangle is given by 2∗(a+a+5)=4a+10 units

Length of a rectangle is $5$ units more than its breadth. Express its perimeter in polynomial form.

Given,
Length of a rectangle is $5$ units more than its breadth.Perimeter is defined as total length of contour.
Let breadth of rectangle be $a$ units then its length will be $a + 5$ units. Then perimeter of rectangle is given by $2 * (a + a + 5) = 4 a + 10$ units