Length of a string of density ρ and Young's modulus Y under tension is increased by 1/n times of its original length. Find the new value of speed of the wave.
A
√Ypn
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B
(Ypn)−12
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C
√Yp
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D
(Ypn)32
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Solution
The correct option is A√Ypn For longitudnal vibrations, v=√Yp, Y=stressstrain=stress(1/n) stress=Tensionarea of cross section of wireA=Yn Tension=YAn For transverse vibrations, v=√Tensionmass of the string of per unit length v=
⎷YAnmass of the string of per unit length v=
⎷YAnpA=√Ynp Option "A" is correct.