Question

Length of minor axis J6, foci(0, ± 6)16.

Answer 1

Given, the length of minor axis is 16 and foci are (0,±6)

Since, the foci are on the y axis, so the equation of the ellipse will be in the form of x 2 b 2 + y 2 a 2 =1.

where, y is the major axis.

Now, the length of minor axis is represented as 2b .

So, 2b=16 b=8

Foci of an ellipse are given as (0,±c)

By comparing with the given values, we get

c=6

Also,

c 2 = a 2 − b 2

6 2 = a 2 − 8 2 a 2 =100 a=±10

Thus, the equation of ellipse with foci ( 0,±6 ) and length of minor axis 16 is x 2 64 + y 2 100 =1 .