Question

Length of parallel lines and heights of trapeziums are given respectively, then find their respective areas.

• A. 9 $c{m}^2$
• B. 10 $c{m}^2$
• C. 16 $c{m}^2$
• D. 18 $c{m}^2$

Answer 1

Area of trapezium =
$\frac{1}{2}$$\times$(Sum of parallel lines)$\times$height

For 2 cm, 4 cm, 3 cm
Area of trapezium
= $\frac{1}{2}$$\times$(2+4)$\times$3 = 9 $c{m}^2$

For 4 cm, 6 cm, 2 cm
Area of trapezium
= $\frac{1}{2}$$\times$(4+6)$\times$2 = 10 $c{m}^2$

For 3 cm, 5 cm, 4 cm
Area of trapezium
= $\frac{1}{2}$$\times$(3+5)$\times$4 = 16 $c{m}^2$

For 5 cm, 7 cm, 3 cm
Area of trapezium
= $\frac{1}{2}$$\times$(5+7)$\times$3 = 18 $c{m}^2$