CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Right-angled Triangle

Question 7 Le...

Question

Question 7

Lengths of sides of a triangle are 3 cm, 4 cm and 5 cm. The triangle is

a) Obtuse-angled triangle
b) Acute angled triangle
c) Right angled triangle
d) An isosceles right triangle.

Open in App

Solution

Lengths of the sides of a triangle are 3 cm, 4 cm and 5 cm
According to Pythagoras theorem,
$3^{2} + 4^{2} = 5^{2} \Rightarrow 9 + 16 = 25 \Rightarrow 25 = 25 (s a t i s f i e d)$

Since these sides satisfy the Pythagoras theorem, therefore it is right angled triangle.

Suggest Corrections

thumbs-up

78

Similar questions

A triangle of sides AB = 5 cm, BC = 4 cm and AC = 3 cm is constructed. Then $△$ ABC is

Question 14

If in an isosceles triangle, each of the base angle is $40^{\circ}$ , then the triangle is

a) Right angled triangle
b) Acute angled triangle
c) Obtuse-angled triangle
d) Isosceles right-angled triangle

Q. Question 4
The angles of a triangle are in the ratio 5 : 3 : 7. The triangle is:

A) An acute-angled triangle
B) An obtuse-angled triangle
C) A right-angled triangle
D) An isosceles triangle

\to x

\to y

are two non-parallel vectors and

A B C

is a triangle with side lengths

a, b

c

(20 a - 15 b) \to x + (15 b - 12 c) \to y + (12 c - 20 a) (\to x \times \to y) = \to 0

, then triangle

A B C

Δ A B C, sin C + cos C + sin (2 B + C) - cos (2 B + C) = 2 \sqrt{2} .

Δ A B C

View More

Join BYJU'S Learning Program

explore_more_icon

Explore more

Right-angled Triangle

Standard VII Mathematics

Join BYJU'S Learning Program

CrossIcon