Let (1,−2) and (−3,4) be two vertices of a triangle whose centroid lies on the line x+3y=2. Then locus of the third vertex of the triangle is
A
x+3y=2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
x+3y=4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x+3y=8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x+3y=16
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Ax+3y=2 Let (α,β) be the third vertex. ∴ Centroid ≡(α+1−33,β−2+43)≡(α−23,β+23) lies on x+3y=2. ⇒(α−23)+3(β+23)=2 ⇒α+3β=2 ∴ Locus of (α,β) is x+3y=2.