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Byju's Answer
Standard XII
Mathematics
Sum of Infinite Terms of a GP
Let 1+ x n =1...
Question
Let
(
1
+
x
)
n
=
1
+
n
x
+
n
(
n
−
1
)
x
2
2
+
⋯
⋯
|
x
|
< 1, n
ϵ
Z
Then the sum of the series
3
+
8
3
+
80
3
3
+
240
3
4
+
.
.
.
.
.
is
A
9
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B
27
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C
12
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D
101
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Solution
The correct option is
B
27
(
1
+
x
)
n
=
3
+
8
3
+
80
3
3
+
240
3
4
+
⋯
=
1
+
n
x
+
n
(
n
−
1
)
x
2
2
+
⋯
i
e
1
+
3
(
2
3
)
+
6
(
2
3
)
2
+
10
(
2
3
)
3
+
15
(
2
3
)
4
+
⋯
Suggest Corrections
1
Similar questions
Q.
Let
(
1
+
x
)
n
=
1
+
n
x
+
n
(
n
−
1
)
x
2
2
+
⋯
|
x
|
<
1
,
n
ϵ
Z
Then the sum of the series
3
+
8
3
+
80
3
3
+
240
3
4
⋯
is
Q.
Sum of n terms of the series
2
+
8
+
18
+
32
+
.
.
i
s
(a)
n
(
n
+
1
)
2
(b)
2
n
(
n
+
1
)
(c)
n
(
n
+
1
)
2
(d) 1