Let 1-x-x2202 x-1-a0-a1 x1-a2 x2-a41 x41 then a0-1-a1-2-a2-3-a41-42 is equal to

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Sum of Coefficients of All Terms

Let 1+x+x2202...

Question

Let $(1 + x + x^{2})^{20} (2 x + 1) = a_{0} + a_{1} x^{1} + a_{2} x^{2} + . . . . . . . . . . + a_{41} x^{41}$ then $\frac{a_{0}}{1} + \frac{a_{1}}{2} + \frac{a_{2}}{3} + . . . . . . . . . . . . \frac{a_{41}}{42}$ is equal to

(\frac{2^{21} - 1}{21})

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(\frac{3^{21} - 1}{21})

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(\frac{2^{20} - 1}{20})

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(\frac{3^{20} - 1}{20})

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Similar questions

(1 + x^{2}) = a_{0} + a_{1} x + a_{2} x^{2} + . . . . + a_{36} x^{36}

a_{0} + a_{3} + a_{6} + . . . + a_{36} = \frac{2}{3} (2^{35} + 1)

a_{0} + a_{1} + a_{2} + . . . + a_{36} = 2^{36}

a_{0} + a_{2} + a_{4} + . . . + a_{36} = 2^{35}

If $(1 + x + 2 x^{2})^{20} = a_{0} + a_{1} + a_{2} x^{2} + . . . + a_{40} x^{40}, t h e n a_{1} + a_{3} + a_{5} + . . . + a_{37} e q u a l s$ :

n \in N

(1 + x + x^{2})^{n} = a_{0} + a_{1} x + a_{2} x^{2} . . . a_{2 n} x^{2 n}

a_{0} + a_{1} + a_{2} . . . . a_{n - 1}

(1 + x + x^{2} + x^{3} + \dots \dots . x^{p})^{n} = a_{0} + a_{1^{X}} + a_{2} x^{2} + \dots . . + a_{n p} x^{n p}

a_{0} + a_{1} + a_{2} + \dots . + a_{n p} =

{(1 - x + x^{4})}^{10} = a_{0} + a_{1} x + a_{2} x^{2} + . . . . . + a_{40} x^{40}

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