Let $15$ toys be distributed among three children such that any child can take any number of toys.Find the required number of ways to do this if toys are identical.

315

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256

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300

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275

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Solution

The correct option is B $256$
$15$ toys and $3$ children
The toys are identical
$\Rightarrow$ Each child can get toys in $16$ ways
(Including the case of not getting any the toy )
Therefore there are
$= 16 \times 16$
$= 256$ Ways

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Let 15 toys be distributed among three children such that any child can take any number of toys.Find the required number of ways to do this if toys are identical.

The correct option is B 25615 toys and 3 children The toys are identical ⇒ Each child can get toys in 16 ways (Including the case of not getting any the toy )Therefore there are =16×16=256 Ways

Let $15$ toys be distributed among three children such that any child can take any number of toys.Find the required number of ways to do this if toys are identical.

The correct option is B $256$
$15$ toys and $3$ children
The toys are identical
$\Rightarrow$ Each child can get toys in $16$ ways
(Including the case of not getting any the toy )
Therefore there are
$= 16 \times 16$
$= 256$ Ways