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Question

Let (āˆ’3,2) be one end of a diameter of a circle with center (4,6). Find the other end of the diameter.

A
(11,10)
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B
(10,2)
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C
(1,1)
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D
(7,5)
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Solution

The correct option is A (11,10)
Let the other end of the diameter be (x,y) and as center is the midpoint of the diameter, we have:
x32=4x=11
y+22=6y=10
So the other end of the diameter is (11,10)
So option A is the right answer.

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