Question

Let $5x^2+7y^2=140$, then Position of $(4,-3)$ relative to the ellipse is

• A. Inside the ellipse.
• B. Outside the ellipse.
• C. On the ellipse.
• D. None of the above.

Answer 1

The correct option is B Outside the ellipse.

Equation of ellipse : ${5x}^2+{7y}^2=140$

putting point (4,3) in equation

$=5\times {\left(4\right)}^2+7{(-3)}^2-140$

$=80+63-140$

$=3(>0)$

Hence, point is outside the ellipse.