Let a0-0 and an-3 an-1-1 for n - 1 then the remainder obtained on dividing a2010 by11 is

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Addition of Polynomials

Let a0=0 an...

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Let $a_{0} = 0$ and $a_{n} = 3 a_{n - 1} + 1$ for $n \geq 1$ then the remainder obtained on dividing $a_{2010}$ by11 is

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n! = 1 \times 2 \times 3 \times . . . . . . . . . . . \times n

n > 1

p = 1! + (2 \times 2!) + (3 \times 3!) + . . . . . . . . . . . + (10 \times 10!),

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(2 x + 1)

(4 x^{3} + p x^{2} - q x + 3)

p, q

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