If A=[1 2−1 3]B=[4 01 5]C=[2 01−2], a = 4, and b = - 2, then show that:
(i) A + (B + C) = (A + B) + C
(ii) A (BC) = (AB) C
(iii) (a + b)B = aB + bB
(iv) a (C - A) = aC - aA
(v) (AT)T = A
(vi) (bA)T = b AT
(vii) (AB)T=BTAT
(viii) (A - B)C = AC - BC
(ix) (A−B)T=AT−BT