Let $A = {1, 2, 3, 4, 5, 6}$ , $B = {2, 4, 6, 8}$ . Find $A - B$ and $B - A$ .

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Solution

$A - B = {x : x \in A a n d x \notin B} = {1, 3, 5}$ Similarly $B - A = {8}$ .

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