Let A -1-2-3-4-5- B -4-5-6-7-8 and C -8-9-10-11-12- then n - A - B - C -

A × (B' ∪ C')' = A × (B ∩ C) nbsp;B∩ C={8} ⇒ n[A × (B' ∪ C')']= 5× 1=5 ...

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Number of Elements in a Cartesian Product

Let A =1,2,3,...

Question

Let $A = {1, 2, 3, 4, 5},$ $B = {4, 5, 6, 7, 8}$ and $C = {8, 9, 10, 11, 12},$ then $n [A \times (B^{'} \cup C^{'})^{'}] =$

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Solution

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Similar questions

A = {1, 2, 3}, B = {4, 5, 6, 7, 8},

C = {4, 6, 8, 10, 12},

n [(A \times B) - (A \times C)] =

If A = {1,2,3,4,5},

B= {4,5,6,7,8} and C= {7,8,9,10,11}

Find :

(i) $A \cup B$ (ii) $A \cup C$

(iii) $B \cup C$

A = {1, 2, 3}, B = {4, 5, 6, 7, 8},

C = {4, 6, 8, 10, 12},

n [(A \times B) - (A \times C)] =

A = {1, 2, 3}, B = {4, 5, 6, 7, 8},

C = {4, 8, 12, 16, 20},

n [(A \times B) \cup (A \times C)] =

A \cup B

A \cup C

B \cup C

B \cup D

A \cup B \cup C

A \cup B \cup D

B \cup C \cup D

A \cap (B \cup C)

(A \cap B) \cap (B \cap C)

(A \cup D) \cap (B \cup C)

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