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Byju's Answer
Standard XI
Mathematics
Symmetric Difference of Sets
Let A =1, 2, ...
Question
Let
A
=
{
1
,
2
,
3
,
4
}
,
B
=
{
2
,
3
,
4
,
5
,
6
}
,
then
A
Δ
B
is
A
{
2
,
3
,
4
}
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B
{
1
}
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C
{
5
,
6
}
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D
{
1
,
5
,
6
}
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Solution
The correct option is
D
{
1
,
5
,
6
}
A
Δ
B
=
(
A
−
B
)
∪
(
B
−
A
)
=
{
1
}
∪
{
5
,
6
}
=
{
1
,
5
,
6
}
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0
Similar questions
Q.
Let
A
=
{
1
,
2
,
3
,
4
}
,
B
=
{
2
,
3
,
4
,
5
,
6
}
,
then
A
Δ
B
is
Q.
Let
A
=
{
1
,
2
,
3
,
4
}
and
B
=
{
2
,
3
,
4
,
5
,
6
}
then
A
△
B
is equal to
Q.
Let
A
=
{
1
,
2
,
3
,
4
}
,
B
=
{
2
,
3
,
4
,
5
,
6
}
,
then
A
Δ
B
=
Q.
Let
A
=
{
1
,
2
,
3
,
4
}
,
B
=
{
2
,
3
,
4
,
5
,
6
}
,
then
A
Δ
B
is
Q.
Let
A
=
{
1
,
2
,
3
,
4
}
and
B
=
{
2
,
3
,
4
,
5
,
6
}
, then
A
△
B
is equal to =?
(
where
A
△
B
is defined as
A
△
B
=
{
x
:
x
∈
A
B
or
x
∈
B
A
}
)
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Symmetric Difference of Sets
Standard XI Mathematics
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