Let A - 1- 2- 3- B - 4- 5- 6- 7- 8- C - 4- 6- 8- 10- 12- then n-A - B- A - C -

A = {1, 2, 3}, B = {4, 5, 6, 7, 8}, C = {4, 6, 8, 10, 12}, (A × B) (A × C) = A × (B C) (B C)= nbsp;{5, 7} n[(A × B) (A × C) ] =n(A × (B C)) =n(A) × n ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Number of Elements in a Cartesian Product

Let A = 1, 2,...

Question

Let $A = {1, 2, 3}, B = {4, 5, 6, 7, 8},$ $C = {4, 6, 8, 10, 12},$ then $n [(A \times B) - (A \times C)] =$

6

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

12

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

24

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $6$
$A = {1, 2, 3}, B = {4, 5, 6, 7, 8},$ $C = {4, 6, 8, 10, 12},$

$(A \times B) - (A \times C) = A \times (B - C) (B - C) = {5, 7}$

$n [(A \times B) - (A \times C)] = n (A \times (B - C)) = n (A) \times n (B - C) = 3 \times 2$
$= 6$

Suggest Corrections

Similar questions

Q. Let

A = {1, 2, 3}, B = {4, 5, 6, 7, 8},

C = {4, 6, 8, 10, 12},

then

n [(A \times B) - (A \times C)] =

Q. If

A = {1, 2, 3}, B = {4, 5, 6, 7, 8},

C = {4, 8, 12, 16, 20},

then

n [(A \times B) \cup (A \times C)] =

Q. If

A = {1, 2, 3}, B = {4, 5, 6, 7, 8},

C = {4, 8, 12, 16, 20},

then

n [(A \times B) \cup (A \times C)] =

Q. Let

A = {1, 2, 3, 4, 5},

B = {4, 5, 6, 7, 8}

and

C = {8, 9, 10, 11, 12},

then

n [A \times (B^{'} \cup C^{'})^{'}] =

Q. Let

A = {1, 2, 3}, B = {2, 4, 6, 8}, C = {2, 3, 5, 6} .

Then

A \cap (B \cup C), . . . . . .

Join BYJU'S Learning Program

Explore more

Number of Elements in a Cartesian Product

Standard XII Mathematics

Join BYJU'S Learning Program

Let A={1,2,3},B={4,5,6,7,8}, C={4,6,8,10,12}, then n[(A×B)−(A×C)]=

The correct option is A 6A={1,2,3},B={4,5,6,7,8}, C={4,6,8,10,12}, (A×B)−(A×C)=A×(B−C)(B−C)={5,7} n[(A×B)−(A×C)]=n(A×(B−C))=n(A)×n(B−C)=3×2 =6

Let $A = {1, 2, 3}, B = {4, 5, 6, 7, 8},$ $C = {4, 6, 8, 10, 12},$ then $n [(A \times B) - (A \times C)] =$

The correct option is A $6$
$A = {1, 2, 3}, B = {4, 5, 6, 7, 8},$ $C = {4, 6, 8, 10, 12},$

$(A \times B) - (A \times C) = A \times (B - C) (B - C) = {5, 7}$

$n [(A \times B) - (A \times C)] = n (A \times (B - C)) = n (A) \times n (B - C) = 3 \times 2$
$= 6$