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Byju's Answer
Standard XI
Mathematics
Number of Elements in a Cartesian Product
Let A =1, 3, ...
Question
Let
A
=
{
1
,
3
,
5
,
7
,
9
,
11
}
,
B
=
{
3
,
9
,
27
,
81
,
243
}
,
then
n
[
(
A
×
B
)
∩
(
B
×
A
)
]
is
Open in App
Solution
(
A
×
B
)
∩
(
B
×
A
)
=
(
A
∩
B
)
×
(
B
∩
A
)
∴
A
∩
B
=
{
3
,
9
}
⇒
2
elements
n
[
(
A
×
B
)
∩
(
B
×
A
)
]
=
2
×
2
=
4
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0
Similar questions
Q.
Let
A
=
{
1
,
3
,
5
,
7
,
9
,
11
}
,
B
=
{
3
,
9
,
27
,
81
,
243
}
,
then
n
[
(
A
×
B
)
∩
(
B
×
A
)
]
is
Q.
If
a
+
b
+
c
=
27
, then what is the value of
(
a
−
7
)
3
+
(
b
−
9
)
3
+
(
c
−
11
)
3
−
3
(
a
−
7
)
(
b
−
9
)
(
c
−
11
)
?
Q.
Let
A
=
{
1
,
3
,
4
,
7
,
11
}
,
B
=
{
1
,
1
,
2
,
5
,
7
,
9
}
and
f
:
A
→
B
be given by
f
=
{
(
1
,
1
)
,
(
3
,
2
)
,
(
4
,
1
)
,
(
7
,
5
)
,
(
11
,
9
)
}
. Then
f
is
Q.
Let
A
=
{
1
,
2
,
3
,
4
,
5
}
,
B
=
{
4
,
5
,
6
,
7
,
8
}
and
C
=
{
8
,
9
,
10
,
11
,
12
}
,
then
n
[
A
×
(
B
′
∪
C
′
)
′
]
=
Q.
Let
a
,
b
∈
R
+
such that
log
27
a
+
log
9
b
=
7
2
and
log
27
b
+
log
9
a
=
2
3
.
Then the value of
a
b
is
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