Let a1-a2-a10 be a G-P- If a3a1-25- then a9a5 equals-

The correct option is C 5^4 a_1,a_2,...,a_10 are in G.P., Let #160; the common ratio be r a_3a_1=25⇒a_1r^2a_1=25 ⇒ r^2=25 a_9a ...

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Sum of Coefficients of All Terms

Let a1,a2,....

Question

Let $a_{1}, a_{2}, . . . . ., a_{10}$ be a G.P. If $\frac{a_{3}}{a_{1}} = 25$ , then $\frac{a_{9}}{a_{5}}$ equals:

2 (5^{2})

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4 (5^{2})

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5^{4}

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5^{3}

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Solution

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Similar questions

a_{1}, a_{2}, \dots, a_{10}

\frac{a_{3}}{a_{1}} = 25

\frac{a_{9}}{a_{5}}

a_{1}, a_{2}, \dots, a_{10}

\frac{a_{3}}{a_{1}} = 25

\frac{a_{9}}{a_{5}}

a, a_{1}, a_{2} . . . . . . . . . . . . . a_{10}, b

a, g_{1}, g_{2} . . . . . . g_{10}, b

h

a

b

\frac{a_{1} + a_{2} + . . . . . . . . . + a_{10}}{g_{1} g_{10}} + \frac{a_{2} + a_{3} + . . . . . . . . . + a_{9}}{g_{2} g_{9}} + . . . . . . . . . . . + \frac{a_{5} + a_{6}}{g_{5} g_{6}}

a_{1}, a_{2}, a_{3}, . . . .

a_{1}, a_{5}, a_{10} + a_{15} + a_{20} + a_{24} = 225

a_{1} + a_{2} + a_{3} + . . . + a_{24}

a_{1}, a_{2}, a_{3}, . . . . . . . . i s a n A . P . s u c h t h a t a_{1} + a_{5} + a_{10} + a_{15} + a_{20} + a_{24} = 225

a_{1} + a_{2} + a_{3} + . . . . . . . + a_{23} + a_{24} i s e q u a l t o

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