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Byju's Answer
Standard XII
Mathematics
Evaluation of a Determinant
Let a1,a2,......
Question
Let
a
1
,
a
2
,
.
.
.
,
a
10
be an AP with common difference
−
3
and
b
1
,
b
2
,
.
.
.
,
b
10
be a GP with common ratio
2.
Let
c
k
=
a
k
+
b
k
,
k
=
1
,
2
,
.
.
.
,
10.
If
c
2
=
12
and
c
3
=
13
,
then
10
∑
k
=
1
c
k
is equal to
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Solution
c
2
=
a
2
+
b
2
=
(
a
1
−
3
)
+
2
b
1
=
12
⇒
a
1
=
11
c
3
=
a
3
+
b
3
=
(
a
1
−
6
)
+
4
b
1
=
13
⇒
b
1
=
2
c
k
=
a
k
+
b
k
=
(
a
1
−
3
(
k
−
1
)
)
+
(
b
1
⋅
2
k
−
1
)
=
(
11
−
3
k
+
3
)
+
(
2
k
)
=
14
−
3
k
+
2
k
10
∑
k
=
1
c
k
=
10
∑
k
=
1
(
2
k
−
3
k
+
14
)
=
10
∑
k
=
1
2
k
−
3
10
∑
k
=
1
k
+
10
∑
k
=
1
14
=
2
(
2
10
−
1
)
−
3
⋅
10
⋅
11
2
+
140
=
2021
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44
Similar questions
Q.
Let
b
i
>
1
for i = 1, 2, .... ,101. Suppose
l
o
g
e
b
1
,
l
o
g
e
b
2
,
…
…
l
o
g
e
b
101
are in AP with the common difference
l
o
g
e
2
. Suppose
a
1
,
a
2
,
…
…
a
101
are in AP, such that
a
1
=
b
1
and
a
51
=
b
51
. If
t
=
b
1
+
b
2
+
…
…
+
b
51
and
s
=
a
1
+
a
2
+
…
…
+
a
51
, then
Q.
Let
a
1
,
a
2
,
a
3
,
…
be an A.P. If
a
1
+
a
2
+
⋯
+
a
10
a
1
+
a
2
+
⋯
+
a
p
=
100
p
2
,
p
≠
10
,
then
a
11
a
10
is equal to
Q.
Let
a
1
,
b
1
,
c
1
be natural numbers. We define
a
2
=
g
c
d
(
b
1
,
c
1
)
,
b
2
=
g
c
d
(
c
1
,
a
1
)
,
c
2
=
g
c
d
(
a
1
,
b
1
)
,
and
a
3
=
l
c
m
(
b
2
,
c
2
)
,
b
3
=
l
c
m
(
c
2
,
a
2
)
,
c
3
=
l
c
m
(
a
2
,
b
2
)
.
Show that
g
c
d
(
b
3
,
c
3
)
=
a
2
.
Q.
Let
C
k
=
n
C
k
for
0
≤
k
≤
n
and
A
k
=
[
C
2
k
−
1
0
0
C
2
k
]
for
k
≥
1
, and
A
1
+
A
2
+
.
.
.
+
A
n
=
[
k
1
0
0
k
2
]
, then
Q.
Let
a
1
a
2
,
b
1
b
2
,
c
1
c
2
be the consecutive terms of an arithmetic progression. If
a
1
x
2
+
2
b
1
x
+
c
1
=
0
and
a
2
x
2
+
2
b
2
x
+
c
2
=
0
have a common root, then
a
2
,
b
2
,
c
2
are in
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