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Question

Let $a_{1}, a_{2}, a_{3}, a_{4}, a_{5}$ be a sequence of five consecutive odd numbers. Consider a new sequence of five cosecutive even numbers ending with 2 $a_{3}$ .
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Solution

Number of terns in the second sequence = 5
3rd term of the second sequence = average of all the 5 terms = 450 / 5 = 90
So, 5th term of the second sequence = 90 + 2 + 2 = 94
3rd term of the first sequence = 94 / 2 = 47
5th term of the first sequence = 47 + 2 + 2 = 51.

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