Let a 1 - a 2 - a 3 - a 4 and b real numbers such that b- K-1 4 a K -8 and b 2 - K-1 4 a K 2 -16- The possible integral value of - b- can be-

The correct option is D 2 b+a_1+a_2+a_3+a_4=8 b^2+a^2_1+a^2_2+a^2_3+a^2_4=16 Now, a^2_1+a^2_2+a^2_3+a^2_4 gt; 0 ⇒ b^2 lt; 16 ...

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Inverse of a Matrix

Let a 1 , a...

Question

Let $a_{1}, a_{2}, a_{3}, a_{4}$ and $b$ real numbers such that $b + 4 \sum K = 1 a_{K} = 8$ and $b^{2} + 4 \sum K = 1 a_{K}^{2} = 16$ . The possible integral value of ' $b$ ' can be:

2

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a_{1}, a_{2}, a_{3}, a_{4}

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a_{1} + a_{2} + a_{3} + a_{4} = 0

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(a_{1} - a_{2})^{2} + (a_{2} - a_{3})^{2} + (a_{3} - a_{4})^{2} + (a_{4} - a_{1})^{2}

a

b

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(a_{1}^{2} + a_{2}^{2} + a_{3}^{2}) b^{2} - 2 (a_{1} a_{2} + a_{2} a_{3} + a_{3} a_{4}) b + (a_{2}^{2} + a_{3}^{2} + a_{4}^{2}) \leq 0

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