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Question

Let a1,a2,a3,. be an A.P. such that a1+a2+....+apa1+a2+a3+....+aq=p3q3;pq. Then a6a21 is equal to:

A
1211861
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B
1141
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C
1211681
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D
4111
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Solution

The correct option is B 1211681
a1+a2+......+apa1+a2+a3+......+aq=p3q3

p2[2a+(p1)d]q2[2a+(q1)d]=p3q3

2a+(p1)d2a+(q1)d=p2q2

putting p=11 and q=41
2a+10d2a+40d=(1141)2

a+5da+2d=1211681

a6a21=1211681

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