Let a1- a2- a3- - be terms of an A-P-If a1-a2-apa1-a2-aq-p2q2- p- q then a6 a21 must be-

The correct options are A Less than 1 D 11/41 Given a _ 1 + a _ 2 + a _ 3 +...+ a _ p / a _ 1 + a _ 2 + a _ 3 +...+ a _ q = p ^ 2 / q ^ 2 nbsp;⇒ ...

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Sum of n Terms

Let a1, a2,...

Question

Let $a_{1}, a_{2}, a_{3}, . . . .$ be terms of an A.P.
If $\frac{a_{1} + a_{2} + . . . . + a_{p}}{a_{1} + a_{2} + . . . . . + a_{q}} = \frac{p^{2}}{q^{2}}, p \neq q$ then $\frac{a_{6}}{a_{21}}$ must be-

Less than 1

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\frac{2}{7}

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\frac{11}{41}

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\frac{7}{2}

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Solution

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Similar questions

a_{1}, a_{2}, a_{3} \dots

I f \frac{a_{1} + a_{2} + \dots a_{p}}{a_{1} + a_{2} + \dots + a_{q}} = \frac{p^{2}}{q^{2}}, p \neq q,

\frac{a_{6}}{a_{21}}

a_{1}, a_{2}, a_{3} \dots

I f \frac{a_{1} + a_{2} + \dots a_{p}}{a_{1} + a_{2} + \dots + a_{q}} = \frac{p^{2}}{q^{2}}, p \neq q,

\frac{a_{6}}{a_{21}}

a_{1}, a_{2}, a_{3} \dots

I f \frac{a_{1} + a_{2} + \dots a_{p}}{a_{1} + a_{2} + \dots + a_{q}} = \frac{p^{2}}{q^{2}}, p \neq q,

\frac{a_{6}}{a_{21}}

a_{1}, a_{2}, a_{3} . . . .

\frac{a_{1} + a_{2} + . . . . + a_{p}}{a_{1} + a_{2} + . . . . + a_{q}} = \frac{p^{2}}{q^{2}}, p \neq q

\frac{a_{6}}{a_{21}}

a_{1}, a_{2}, a_{3}, . . . .

\frac{a_{1} + a_{2} + . . . . + a_{p}}{a_{1} + a_{2} + . . . . + a_{q}} = \frac{p^{2}}{q^{2}}

p \neq q

\frac{a_{6}}{a_{21}}

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