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Question

Let a1,a2,a3 be terms of A.P.
If a1+a2+apa1+a2++aq=p2q2,pq, then a6a21 equal

A
4111
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B
72
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C
27
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D
1141
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Solution

The correct option is D 1141
p2[2a1+(p1)d]q2[2a1+(q1)d]=p2q22a1+(p1)d2a1+(q1)d=pqa1+(p12)da1+(q12)d=pqFor a6a21, p=11,q=41a6a21=1141

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