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Question

Let a1,a2,a3,a9 be in harmonic progression. If a4=5 and a5=4, then the value of ∣ ∣ ∣1/a11/a21/a31/a41/a51/a61/a71/a81/a9∣ ∣ ∣ is

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Solution

a1,a2,a3,a9 are in H.P.
an=1a+(n1)d
a4=1a+3d=5
a+3d=15 (1)
Also, a5=1a+4d=4
a+4d=14 (2)
Solving (1) and (2), we get
a=d=120
an=20n1an=n20

Now, let Δ=∣ ∣ ∣1/a11/a21/a31/a41/a51/a61/a71/a81/a9∣ ∣ ∣

=∣ ∣ ∣ ∣ ∣ ∣120220320420520620720820920∣ ∣ ∣ ∣ ∣ ∣

Δ=1(20)3∣ ∣123456789∣ ∣

Applying R3R3R2, then R2R2R1, we get
Δ=1(20)3∣ ∣123333333∣ ∣=0

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