wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let a1,a2,a3, be terms of an A.P. If a1+a2++apa1+a2++aq=p2q2,pq then what is the value of a6a21? [3 MARKS]

Open in App
Solution

Concept: 1 Mark
Application: 2 Marks

a1,a2,a3, be terms of AP

a1+a2++apa1+a2++aq=p2q2

p2[2a1+(p1)d]q2[2a1+(q1)d]=p2q2

2a1+(p1)d2a1+(q1)d=pq

[2a1+(p1)d]q=[2a1+(q1)d]p

2a1(qp)=d[(q1)p(p1)q]

2a1(qp)=d(qp)

2a1=d

a6a21=a1+5da1+20d=a1+10a1a1+40a1=1141

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Sum of n Terms
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon