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Question

Let a1,a2,....an be fixed real numbers and let

f(x)=(xa1)(xa2)(xa3)...(xan).

Find limxa1f(x),

If a a1,a2,...an,compute limxaf(x)

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Solution

limxa+1f(x)=limh0f(a1+h)

limh0|(a1+ha1)(a1+ha2)(a1+ha3)...(a1+han)|

=limh0|h(a1+ha2)(a1+ha3)...(a1+han)|

=(0×(a1a2)×(a1a3)×...×(a1an)=0.

limxa1f(x)=limh0f(a1h)

=limh0{(a1ha1)(a1ha2)(a1ha3)...(a1han)}

=limh0{(h)(a1ha2)(a1ha3)...(a1han)}

={0×(a1a2)×(a1ha3)×...×(a1an)}=0.

limxa+1f(x)=limxa1f(x)=0.

Hencelimxa1

For any a a1,a2,,,,an,we have

limxaf(x)=limxa{(xa1)(xa2)(xa3)...(xan).}

=(aa1)(aa2)(aa3)...(xan).


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