Let A ={1,2,3},B={4,5,6,7} and let f={(1,4),(2,5),(3,6)} be a function from A to B. Show that f is one-one.
Given that A={1,2,3}and B={4,5,6,7}
Now, f:A→B is defined as f={(1,4),(2,5),(3,6)}
Therefore, f(1)=4, f(2)=5, f(3)=6
It is seen that the images of distinct elements of A under f are distinct.
Hence, function f is one-one.