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Question

Let A=2¯i+4¯¯¯k, B=5¯i+33¯j+4¯¯¯k,C=23¯j+¯¯¯k, D=2¯i+¯¯¯k then the value of CD in terms ofAB is

A
AB
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B
13AB
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C
23AB
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D
14AB
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Solution

The correct option is C 23AB
CD=2^i+^k(23^j+^k)
CD=2^i+23^j ________(1)
AB=(5^i+33^j+4^k)(2^i+4^k)
AB=3^i+33^j _________(2)
23AB=CD

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