CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let a=2i+j2k and b=i+j. If c is a vector such that a.c=|c|,|ca|=22 and the angle between a×b and c is 300 then |(a×b)×c| is equal to

A
23
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
32
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 32
We have, a×b=2i2j+k
|(a×b)×c|=|a×b||c|sin300
=22+(2)2+12|c|12=32|c|
Given |ca|=22
(ca)2=9|c|2+|a|22c.a=8
|c|22|c|+1=0(|c|1)2=0|c|=1
|(a×b)×c|=32

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Fundamental Theorem of Calculus
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon