Let A={9,10,11,12,13} and f:A→N be defined by f(n)= highest prime factor of n, then its range is
A
{13}
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B
{3,5,11,13}
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C
{11,13}
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D
{2,3,5,11}
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Solution
The correct option is B{3,5,11,13} A={9,10,11,12,13} f(A)= highest prime factor of A ∴ Highest prime factor of 9=3 Highest prime factor of 10=5 Highest prime factor of 11=11 Highest prime factor of 12=3 Highest prime factor of 13=13 So range of f is {3,5,11,13}