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Byju's Answer
Standard XI
Mathematics
Ordered Pair
Let A=a,b,c:a...
Question
Let
A
=
{
(
a
,
b
,
c
)
:
a
,
b
,
c
∈
N
,
a
(
b
c
)
=
64
}
,
then the total number of ordered triplets is
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Solution
a
(
b
c
)
=
64
64
=
2
6
=
4
3
=
8
2
=
64
1
If
a
=
2
, then
b
c
=
6
b
=
2
,
c
=
3
;
b
=
3
,
c
=
2
;
b
=
1
,
c
=
6
;
b
=
6
,
c
=
1
If
a
=
4
, then
b
c
=
3
b
=
1
,
c
=
3
;
b
=
3
,
c
=
1
If
a
=
8
, then
b
c
=
2
b
=
1
,
c
=
2
;
b
=
2
,
c
=
1
If
a
=
64
, then
b
c
=
1
b
=
1
,
c
=
1
Total number of ordered triplets
=
4
+
2
+
2
+
1
=
9
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0
Similar questions
Q.
Let
A
=
{
(
a
,
b
,
c
)
:
a
,
b
,
c
∈
N
,
a
(
b
c
)
=
64
}
,
then the total number of ordered triplets is
Q.
If
A
=
{
(
a
,
b
,
c
)
:
a
,
b
,
c
are prime numbers and
a
+
b
+
c
=
9
}
, then the number of ordered triplets is
Q.
If
A
=
{
(
a
,
b
,
c
)
:
a
,
b
,
c
are prime numbers and
a
+
b
+
c
=
9
}
, then the number of ordered triplets is
Q.
Number of ordered triplets of natural number (a, b, c) for which
a
b
c
≤
11
is
Q.
Let
n
1
and
n
2
represent respectively the number of possible ordered and unordered triplets
(
a
,
b
,
c
)
such that
a
b
c
=
144
,
(
a
,
b
,
c
∈
N
)
, then
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