Let A - a- b- c- d- B - b- c- e- f- then nA-B - B-A -

The correct option is A 4A = nbsp;{a, b, c, d}, B = {b, c, e, f} A B = nbsp;{a,d}, B A = {e, f} ∴ n((A B) × (B A)) =n(A B) × n(B A) = 2 × 2 = 4 nbs ...

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Standard XII

Mathematics

Number of Elements in a Cartesian Product

Let A = a, b,...

Question

Let $A = {a, b, c, d},$ $B = {b, c, e, f},$ then $n ((A - B) \times (B - A)) =$

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Solution

The correct option is A $4$
$A = {a, b, c, d},$ $B = {b, c, e, f}$
$A - B = {a, d}, B - A = {e, f}$

$∴ n ((A - B) \times (B - A)) = n (A - B) \times n (B - A) = 2 \times 2 = 4$

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Let A={a,b,c,d}, B={b,c,e,f}, then n((A−B)×(B−A))=

The correct option is A 4A={a,b,c,d}, B={b,c,e,f} A−B={a,d}, B−A={e,f} ∴n((A−B)×(B−A))=n(A−B)×n(B−A)=2×2=4

Let $A = {a, b, c, d},$ $B = {b, c, e, f},$ then $n ((A - B) \times (B - A)) =$

The correct option is A $4$
$A = {a, b, c, d},$ $B = {b, c, e, f}$
$A - B = {a, d}, B - A = {e, f}$

$∴ n ((A - B) \times (B - A)) = n (A - B) \times n (B - A) = 2 \times 2 = 4$