Let A=[aij] is a diagonal matrix of order 4 and k is the possible number of zeros in A. Then k can be
A
16
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B
13
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C
14
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D
12
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Solution
The correct option is D12 A=[aij] is a diagonal matrix of order(n)=4
So, maximum number of Zeros are n2−1=16−1=15 and
minimum number of zeros are n2−n=16−4=12 ∴k∈{12,13,14,15}