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Byju's Answer
Standard XII
Mathematics
Sequence
Let A = [ai...
Question
Let
A
=
[
a
i
j
]
n
×
n
be a square matirx and let
c
i
j
be cofactor of
a
i
j
in A. If
C
=
[
c
i
j
]
, then
A
|
C
|
=
|
A
|
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B
|
C
|
=
|
A
|
n
−
1
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C
|
C
|
=
|
A
|
n
−
2
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D
none of these
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Solution
The correct option is
D
|
C
|
=
|
A
|
n
−
1
C
→
Cofactor matrix
A
d
j
A
=
(
C
)
T
But det of
A
d
j
A
=
D
e
t
o
f
C
Because they are transpore of each other .
⇒
|
A
d
j
A
|
=
|
C
|
=
|
A
|
n
−
1
Option-B
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