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Properties of Set Operation

Let A and B a...

Question

Let $A$ and $B$ are two sets. Then $n (A^{C} \cap B^{C}) =$

A

n (U) - n (A \cap B)

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B

n (U) - n (A \cup B)

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C

n (U) - n (A^{C} \cup B)

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D

n (A) + n (B)

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Solution

The correct option is B $n (U) - n (A \cup B)$
$n (A^{C} \cap B^{C}) = n (A \cup B)^{C} = n (U) - n (A \cup B)$

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Similar questions

n (U) = 700, n (A) = 200, n (B) = 300

n (A \cap B) = 100

n (A^{c} \cap B^{c}) =

n (U) = 700, n (A) = 200, n (B) = 300

n (A \cap B) = 100

n (A^{c} \cap B^{c}) =

n (U) = 700, n (A) = 200, n (B) = 300

n (A \cap B) = 100

n (A^{c} \cap B^{c})

A, B

be two sets then prove that

A^{c} - B^{c} = B - A

n (U) = 700

n (A) = 200

n (B) = 300

n (A \cap B) = 100

n (A^{C} \cap B^{C}) =

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