CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let A and B be finte alphabets and let # be a symbol outside both A and B. Let f be a total function from A* to B*. We say f is computable if there exists a Turing machine M which given an input x in A*, always halts with f(x) on its tape. Let L1 denote the language {x # f(x) | x ϵ A*}. Which of the following statements is true:

A

If f is computable then Lf is recursively enumerable, but not conversely.

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

f is computable if and only if Lf is recursive.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

If f is computable then Lf is recursive, but not conversely.

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

f is computable if and only if Lf is recursively enumerable.

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

f is computable if and only if Lf is recursive.


Since the way computable is defined based on halting TM,it means computable is same as Recursive.
So,clearly f is computable iff Lf is recursive.

Since the way computable is defined based on halting TM, it means computable is same as Recursive.
So, clearly f is computable iff Lf is recursive.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Watch in App
Join BYJU'S Learning Program
CrossIcon